f(2)=2^2-4(2)+3

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Solution for f(2)=2^2-4(2)+3 equation: 



f(2)=2^2-4(2)+3

We move all terms to the left:

f(2)-(2^2-4(2)+3)=0

We add all the numbers together, and all the variables

f^2+35=0

a = 1; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·1·35
Δ = -140
Delta is less than zero, so there is no solution for the equation

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